this post was submitted on 30 Aug 2026
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So, A0 has an area of 1 m^2^ and it's halved for each next one in the series, giving A85 a surface area of 1/(2^85^) m^2^ = 2.585×10^-26^ m^2^ = 0.02585 pm^2^.
The smallest atom is the hydrogen atom with a Van der Waals radius of 120 pm which gives it a surface area of 4×π×120^2^ pm^2^ = 180956 pm^2^ or just over 7 million times larger than the A85.